A+B+C = 6 ——> Eq. 1

A*B = 2 ——–> Eq. 2

B*C = 6 ——–> Eq. 3

Case 1: Let say A=2 and B=1 => A*B = 2*1 = 2 This satisfies Eq. 2

Now, Putting above value in Eq. 1 => C= 3 —–> Eq. (4)

Put values of B and C in Eq. (3)

B*C = 1 * 3 = 3 != 6, This does not satisfies Eq. (3). Hence, A and B can not be 2 and 1.

Case 2: Let flip assumed values of A and B, thus new values of A=1 and B=2

Using these values Eq. (2) is satisfied i.e., A*B = 1*2 = 2

Again, using these values in Eq. (1) gives C = 3

Substitute, B = 2 and C = 3 in Eq. (3): B* C = 2*3 = 6

Since, assumed values of A = 1, B = 2 and C = 3 satisfies all above equations

C*A = 3 * 1 = 3

Therefore, C*A = 3 is the answer.

]]>The answer is explained below:

P : Probability

G: Green ball

R: Red ball

Most X = lesser than and equal to X => X is number of balls of any color

P(most 3 G)= P(0 G) + P(1 G) + P(2 G) + P(3 G)

P(<=3G) = (12C5 + 12C4*8C1 + 12C3*8C2 + 12C2*8C3)/20C5 [nCr = {n!/(r!*(n-r)!)]

Answer: d) None

]]>Hence , the image of ( 1,6,3) is ( 1,O,7) ]]>

Answer= the probability or sum of 9 is 1/9 .

d) 1/9

]]>A Concave lens is required to correct a myopic vision.

Also , given , far point of a myopic person

ANSWER= 1.25 D

]]>c) 25 cm

]]>